Find x so the distance between (x,−1) and (4x−2,5) is 10

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Find x so the distance between (x,−1) and (4x−2,5) is 10

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Yến Oanh 4 years 2021-08-25T11:03:39+00:00 1 Answers 8 views 0

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  1. ngochoa
    0
    2021-08-25T11:05:20+00:00
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    Answer:

    x = \dfrac{10}{3}~~or~~x = -2

    Step-by-step explanation:

    (x,−1) and (4x−2,5) is 10

    \sqrt{(4x - 2 - x)^2 + (-1 - 5)^2} = 10

    (3x - 2)^2 + (-6)^2 = 100

    9x^2 - 12x + 4 + 36 = 100

    9x^2 - 12x + 40 = 100

    9x^2 - 12x - 60 = 0

    3x^2 - 4x - 20 = 0

    3x^2 - 10x + 6x - 20 = 0

    x(3x - 10) + 2(3x - 10) = 0

    (3x - 10)(x + 2) = 0

    x = \dfrac{10}{3}~~or~~x = -2

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )