Find x so the distance between (x,−1) and (4x−2,5) is 10

Question

ngochoa · Answer

Answer:    x =  dfrac{10}{3}~~or~~x = -2    Step-by-step explanation:   (x,−1) and (4x−2,5) is 10    sqrt{(4x - 2 - x)^2 + (-1 - 5)^2} = 10    (3x - 2)^2 + (-6)^2 = 100    9x^2 - 12x + 4 + 36 = 100    9x^2 - 12x + 40 = 100    9x^2 - 12x - 60 = 0    3x^2 - 4x - 20 = 0    3x^2 - 10x + 6x - 20 = 0    x(3x - 10) + 2(3x - 10) = 0    (3x - 10)(x + 2) = 0    x =  dfrac{10}{3}~~or~~x = -2

Leave a Comment Cancel reply