Find x so that B = 3x i +5j is perpendicular to is perpendicular to A=2i – 6j August 2, 2021 by Cherry Find x so that B = 3x i +5j is perpendicular to is perpendicular to A=2i – 6j

Answer: 5 Step-by-step explanation: I’m going to call x, x1 because I want to use x as a variable. So we have a ray with points (0,0) and (3×1,5) on it. This equation for this ray would be y=5/(3×1)×x. We have another ray with points (0,0) and (2,-6). This equation for this ray would be y=-6/2×x or y=-3x. We want these two lines’ slopes to be opposite reciprocals. The opposite reciprocal of -3 is 1/3. So we want to find x1 such that 5/(3×1)=1/3. Cross multiply: 15=3×1 Divide both sides by 3: 5=x1 We want x1 to be 5 so that 5/(3×5) and -3 are opposite reciprocals which they are. Another way: If two vectors are perpendicular, then their dot product is 0. The dot product of <3x,5> and <2,-6> is 3x(2)+5(-6). Let’s simplify: 6x-30. We want this to be 0. 6x-30=0 Add 30 on both sides: 6x=30 Divide both sides by 6: x=5 Reply

Answer:

5

Step-by-step explanation:

I’m going to call x, x1 because I want to use x as a variable.

So we have a ray with points (0,0) and (3×1,5) on it. This equation for this ray would be y=5/(3×1)×x.

We have another ray with points (0,0) and (2,-6). This equation for this ray would be y=-6/2×x or y=-3x.

We want these two lines’ slopes to be opposite reciprocals. The opposite reciprocal of -3 is 1/3.

So we want to find x1 such that 5/(3×1)=1/3.

Cross multiply: 15=3×1

Divide both sides by 3: 5=x1

We want x1 to be 5 so that 5/(3×5) and -3 are opposite reciprocals which they are.

Another way:

If two vectors are perpendicular, then their dot product is 0.

The dot product of <3x,5> and <2,-6> is 3x(2)+5(-6).

Let’s simplify:

6x-30.

We want this to be 0.

6x-30=0

Add 30 on both sides:

6x=30

Divide both sides by 6:

x=5