Find all the roots of the equation {x}^{6} - 64 = 0 ​

Question

Find all the roots of the equation
{x}^{6} - 64 = 0
​

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Latifah 3 years 2021-07-31T21:04:13+00:00 2 Answers 10 views 0

Answers ( )

  1. niczorrrr
    0
    2021-07-31T21:05:42+00:00
    Reply

    Answer:

    x = 2

    x =-2

    x =1 +√3i

    x =1 -√3i

    x =-1 +√3i

    x =-1 -√3i  

    Step-by-step explanation:

    x^{6} -64 = 0\\(x^{3} -8)(x^{3} + 8) = 0\\ \\( x - 2) (x^{2} + 2x + 4)( x + 2) (x^{2} -2x + 4) = 0\\

    x = 2

    x =-2

    x =1 +√3i

    x =1 -√3i

    x =-1 +√3i

    x =-1 -√3i  

     

     

     

     

     

     

     

  2. binhan
    0
    2021-07-31T21:05:51+00:00
    Reply

    Standard form:
    X^2 -64=0
    Factorization:
    (x+8)(x-8)=0

    Solution:
    X+8=0 x^1=-8
    X-7=0. X^2=8

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )