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Mn ơi giúp mik vs ạCảm ơn mn nhiều ❤️❤️❤️
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Eirian
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Answers ( )
a,
ĐK: $2-3m\le -2$
$\Leftrightarrow 3m\ge 4$
$\Leftrightarrow m\ge \dfrac{4}{3}$
$\Rightarrow m\in\Big[\dfrac{4}{3};+\infty)$
b,
ĐK: $3\le 2m-5$ hoặc $2m+4\le -1$
$\Leftrightarrow m\ge 4$ hoặc $m\le -\dfrac{5}{2}$
$\Rightarrow m\in(-\infty;-\dfrac{5}{2}\Big]\cup[4;+\infty)$
c,
ĐK: $5-3m\le -2$ hoặc $2<-3m-2$
$\Leftrightarrow m\ge \dfrac{7}{3}$ hoặc $m<\dfrac{-4}{3}$
$\Rightarrow m\in(-\infty;\dfrac{-4}{3}\Big)\cup\Big[\dfrac{7}{3};+\infty)$
`a)`
`<=> 2 – 3m < -2`
`<=> -3m < -4`
`<=> m > 4/3`
`b)`
\(\left[ \begin{array}{l}2m + 4 < -1\\2m – 5 > 3\end{array} \right.\)
`<=>` \(\left[ \begin{array}{l}m < -\dfrac{5}{2}\\m > 4\end{array} \right.\)
`=> m ∈ (-∞; -5/2) ∪ (4; +∞)`
`c)`
`ĐK: 5 – 3m > -3m + 2`
`=> 0m > -3`
`=> D = RR`
\(\left[ \begin{array}{l}5 – 3m < -2\\-3m – 2 ≥ 2\end{array} \right.\)
`<=>` \(\left[ \begin{array}{l}m > \dfrac{7}{3}\\m ≤ \dfrac{-4}{3}\end{array} \right.\)
`=> m ∈ (-∞; -4/3] ∪ (7; 3)`