f^3+11g-4hf 3 +11g−4hf, cubed, plus, 11, g, minus, 4, h when f=3f=3f, equals, 3, g=2g=2g, equals, 2 and h=7h=7h, equals, 7.

Question

f^3+11g-4hf 3 +11g−4hf, cubed, plus, 11, g, minus, 4, h when f=3f=3f, equals, 3, g=2g=2g, equals, 2 and h=7h=7h, equals, 7.

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Mộc Miên 5 years 2021-09-03T10:47:56+00:00 1 Answers 33 views 0

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    2021-09-03T10:49:50+00:00

    Given:

    The expression is:

    f^3+11g-4h

    The given values are f=3,\ g=2,\ h=7.

    To find:

    The value of the given expression for the given values.

    Solution:

    We have,

    f^3+11g-4h

    After substituting f=3,\ g=2,\ h=7, we get

    f^3+11g-4h=(3)^3+11(2)-4(7)

    f^3+11g-4h=27+22-28

    f^3+11g-4h=49-28

    f^3+11g-4h=21

    Therefore, the value of the given expression is 21.

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