Evaluate. Type “no real solution” if no real solutions exist. f() = (x+2)^2 – 3 f(3)= f(-2)= f(0)= f(-4) =

Question

Evaluate. Type “no real solution” if no real solutions exist.
f() = (x+2)^2 – 3
f(3)=
f(-2)=
f(0)=
f(-4) =

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Edana Edana 4 years 2021-08-09T12:02:43+00:00 1 Answers 15 views 0

Answers ( )

  1. thienhuong
    0
    2021-08-09T12:04:34+00:00
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    Answer: If there is no real solution, enter NO REAL SOLUTION.)  Find all solutions of the equation and express them in the form  x^3 − 2x^2 − 7x + 14 = 0. -separate the problem into factoring: x^3 and 2x^2 will be the outside numbers √(x + 42)=x … Use f(x) = 4x − 3 and g(x) = 5 − x^2 to evaluate the expression. (f o g) (-2)

    Step-by-step explanation:

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )