Evaluate. Type “no real solution” if no real solutions exist.
f() = (x+2)^2 – 3
f(3)=
f(-2)=
f(0)=
f(-4) =

Answer: If there is no real solution, enter NO REAL SOLUTION.) Find all solutions of the equation and express them in the form x^3 − 2x^2 − 7x + 14 = 0. -separate the problem into factoring: x^3 and 2x^2 will be the outside numbers √(x + 42)=x … Use f(x) = 4x − 3 and g(x) = 5 − x^2 to evaluate the expression. (f o g) (-2)

Answer: If there is no real solution, enter NO REAL SOLUTION.) Find all solutions of the equation and express them in the form x^3 − 2x^2 − 7x + 14 = 0. -separate the problem into factoring: x^3 and 2x^2 will be the outside numbers √(x + 42)=x … Use f(x) = 4x − 3 and g(x) = 5 − x^2 to evaluate the expression. (f o g) (-2)Step-by-step explanation: