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Eight years ago, the daughters age was thrice the son’s age. Now the daughter’s age is 4 years more than the son’s age. Find their present a
Question
Eight years ago, the daughters age was thrice the son’s age. Now the daughter’s age is 4 years more than the son’s age. Find their present ages.
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Mathematics
5 years
2021-07-18T09:57:54+00:00
2021-07-18T09:57:54+00:00 1 Answers
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Answer:
Let s be the son’s current age and d be the daughter’s current age. The system of equations is:
s – 10 = 2(d – 10)
s = 3 + d
Since s is already set to an equation, we can use the substitution method for s in the other equation:
s = 3 + d
s – 10 = 2(d – 10)
3 + d – 10 = 2(d – 10)
Simplify and solve for d:
3 + d – 10 = 2(d – 10)
-7 + d = 2d – 20
-7 = d – 20
13 = d
The daughter is 13 years old. To solve for the son’s age, we will plug in the solution for d into one of the equations. The second one is simpler so we will use that:
s = 3 + d
s = 3 + 13
s = 16
The son is 16 years old. Let us use the other equation to check our solutions:
s – 10 = 2(d – 10)
16 – 10 = 2(13 – 10)
6 = 2(3)
6 = 6
It checks out. The son is 16 years old, and the daughter is 13 years old.