Divided 29 into two parts so that the sum of the squares of the parts is 425 . Find the value of each part. August 1, 2021 by Ben Gia Divided 29 into two parts so that the sum of the squares of the parts is 425 . Find the value of each part.

Answer: Step-by-step explanation: Equations x + y = 29 x^2 + y^2 = 425 Solution y = 29 – x x^2 + (29 – x)^2 = 425 x^2 + (841 – 58x + x^2 ) = 425 x^2 – 58x + x^2 + 841 – 425 = 0 2x^2 – 58x +416 = 0 a = 2 b = – 58 c = 416 You get two answers that look valid 2x^2 – 58x + 416 = 0 x^2 – 29x + 208 = 0 This factors (x – 16)(x – 13) = 0 x = 16 y = 13 Now check it 16^2 + 13^2 = ? 425 256 + 169 = 425 Reply

Answer:Step-by-step explanation:Equations

x + y = 29

x^2 + y^2 = 425

Solution

y = 29 – x

x^2 + (29 – x)^2 = 425

x^2 + (841 – 58x + x^2 ) = 425

x^2 – 58x + x^2 + 841 – 425 = 0

2x^2 – 58x +416 = 0

a = 2

b = – 58

c = 416

You get two answers that look valid

2x^2 – 58x + 416 = 0

x^2 – 29x + 208 = 0 This factors

(x – 16)(x – 13) = 0

x = 16

y = 13

Now check it

16^2 + 13^2 = ? 425

256 + 169 = 425