Đạo hàm v. y=(1+tanx)^2 w. $y=\sqrt{tan\dfrac{x}{2}}$ y. $ \sqrt{2+tan^2x}$

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Đạo hàm
v. y=(1+tanx)^2
w. $y=\sqrt{tan\dfrac{x}{2}}$
y. $ \sqrt{2+tan^2x}$

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King 5 years 2021-05-18T09:40:47+00:00 1 Answers 40 views 0

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  1. RobertKer
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    2021-05-18T09:41:58+00:00
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