CF4 + Br2 CBr4 + F2 Mole Ratio? How many moles of F2 can you make from 57 g of CF4? How many grams of Br2 do you hav

Question

CF4 + Br2 CBr4 + F2

Mole Ratio?
How many moles of F2 can you make from 57 g of CF4?
How many grams of Br2 do you have if you made 250 g of CBr4?
How many moles of F2 can you make from 4.8 mol of CF4?

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Gia Bảo 5 years 2021-08-19T03:49:25+00:00 1 Answers 49 views 0

Answers ( )

  1. nguyetanh
    0
    2021-08-19T03:51:07+00:00
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    Answer:

    Answers are in the explanation

    Explanation:

    Based on the reaction:

    CF₄ + 2Br₂ → CBr₄ + 2F₂

    The mole ratio of CF₄ is:

    CF₄:Br₂ = 1:2

    CF₄:CBr₄ = 1:1

    CF₄:F₂ = 1:2

    Moles F2:

    Molar mass CF₄: 88.0g/mol

    57.0g * (1mol / 88.0g) = 0.6477 moles CF₄ * (2mol F₂ / 1mol CBr₄) =

    1.30 moles F₂

    Mass Br2:

    Molar mass CBr₄: 331.63g/mol

    250.0g * (1mol / 331.63g) = 0.7539 moles CBr₄ * (2mol Br₂ / 1mol CF₄) =

    1.51 moles Br₂ * (159.808g / mol) =

    241g Br2

    Moles F2:

    4.8 moles CF₄ * (2mol F₂ / 1mol CF₄) =

    9.6 moles F₂

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