Calculate the value of the equilibrium constant for the following system, where the concentrations of reactants and products are: [NO]=1.2×1

Question

Calculate the value of the equilibrium constant for the following system, where the concentrations of reactants and products are: [NO]=1.2×10^-3M , [NO2]=1.5×10-^1M , [N2O]=2.4×10^-3M

in progress 0
Verity 5 years 2021-09-05T10:28:05+00:00 1 Answers 29 views 0

Answers ( )

  1. diemkieu
    0
    2021-09-05T10:29:37+00:00
    Reply

    Answer:

    The equilibrium constant is 2.08×10⁵

    Explanation:

    Based on the reaction:

    3NO ⇄ N₂O + NO₂

    The equilibrium constant, k, is defined as:

    k = [NO₂] [N₂O] / [NO]³

    Where the [] is the molarity in equilibrium of each specie.

    Computing te values of the problem:

    k = [1.5×10⁻¹M] [2.4×10⁻³M] / [1.2×10⁻³M]³

    k = 2.08×10⁵

    The equilibrium constant is 2.08×10⁵

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )