Calculate the number of grams in 260 mL ( 1000mL = 1 L) of a 0.55 M solution of NaCl. (1 mol = 58 g)

Question

Calculate the number of grams in 260 mL ( 1000mL = 1 L) of a 0.55 M solution of NaCl. (1
mol = 58 g)

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Thanh Thu 5 years 2021-08-07T14:58:27+00:00 1 Answers 46 views 0

Answers ( )

  1. lethu
    0
    2021-08-07T14:59:49+00:00
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    Answer:

    8.29g NaCl are present

    Explanation:

    To solve this question we must, as first, find the moles of NaCl in 260mL of the solution. These moles can be converted to grams using its molar mass (NaCl = 58g/mol)

    Moles NaCl:

    260mL * (1L / 1000mL) = 0.260L * (0.55mol / L) = 0.143 moles NaCl

    Mass NaCl:

    0.143 moles NaCl * (58g / mol) = 8.29g NaCl are present

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