Calculate the mass of 1 Mole of Copper(ii) sulfate pentahydrate​

Question

Calculate the mass of 1 Mole of Copper(ii) sulfate pentahydrate​

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Trung Dũng 5 years 2021-07-13T01:59:34+00:00 1 Answers 34 views 0

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  1. quangkhai
    0
    2021-07-13T02:01:28+00:00
    Reply

    Answer:

    200 g CuSO₄ · 5H₂O

    General Formulas and Concepts:

    Math

    Pre-Algebra

    Order of Operations: BPEMDAS

    1. Brackets
    2. Parenthesis
    3. Exponents
    4. Multiplication
    5. Division
    6. Addition
    7. Subtraction
    • Left to Right

    Chemistry

    Atomic Structure

    • Reading a Periodic Table
    • Moles
    • Compounds

    Organic

    • Prefix roots

    Reactions

    • Salts
    • Anhydride Salts
    • Hydrates

    Stoichiometry

    • Using Dimensional Analysis

    Explanation:

    Step 1: Define

    [Given] 1 mol CuSO₄ · 5H₂O (Copper II sulfate pentahydrate)

    Step 2: Identify Conversions

    [PT] Molar Mass of Cu – 63.55 g/mol

    [PT] Molar Mass of S – 32.07 g/mol

    [PT] Molar Mass of O – 16.00 g/mol

    [PT] Molar Mass of H – 1.01 g/mol

    Molar Mass of CuSO₄ – 63.55 + 32.07 + 4(16.00) = 159.62 g/mol

    Molar Mass of H₂O – 2(1.01) + 16.00 = 18.02 g/mol

    Step 3: Convert

    There is 5 moles of water added for every one mole of Copper II Sulfate present.

    1. [DA] Set up:                                                                                                     \displaystyle 1 \ mol \ CuSO_4(\frac{159.62 \ g \ CuSO_4}{1 \ mol \ CuSO_4}) + 5 \ mol \ H_2O(\frac{18.02 \ g \ H_2O}{1 \ mol \ H_2O})
    2. [DA] Multiply/Divide [Cancel out units]:                                                         \displaystyle 159.62 \ g \ CuSO_4 + 90.1 \ g \ H_2O
    3. [DA] Add:                                                                                                         \displaystyle 249.72 \ g \ CuSO_4 \cdot 5H_2O

    Step 4: Check

    Follow sig fig rules and round. We are given 1 sig fig.

    249.72 g CuSO₄ · 5H₂O ≈ 200 g CuSO₄ · 5H₂O

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