Calculate the approximate temperature of a 0.50 mol sample of gas at 2.7 atm and a volume of 1.20L

Question

Calculate the approximate temperature of a 0.50 mol sample of gas at 2.7 atm and a volume of 1.20L

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RobertKer 5 years 2021-08-09T09:45:32+00:00 1 Answers 24 views 0

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    2021-08-09T09:47:13+00:00

    Answer:

    79.0 K

    Explanation:

    Assuming the gas behaves like an ideal gas, we can solve this problem by using the following formula:

    • PV = nRT

    Where:

    • P = 2.7 atm
    • V = 1.20 L
    • n = 0.50 mol
    • R = 0.082 atm·L·mol⁻¹·K⁻¹ (it is a constant)
    • T = ?

    We input the data:

    • 2.7 atm * 1.20 L = 0.50 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * T

    And solve for T:

    • T = 79.0 K

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