C

What is the equation of the line that is parallel to the line y – 1 = 4(x + 3) and passes through the point (4, 32)?

SER

O y=-*x+33

y=-*x+36

O y =

O y = 4x – 16

O y = 4x + 16

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What is the equation of the line that is parallel to the line y – 1 = 4(x + 3) and passes through the point (4, 32)?

SER

O y=-*x+33

y=-*x+36

O y =

O y = 4x – 16

O y = 4x + 16

Mark this and retum

Save and Exit

Nex

Submit

9514 1404 393

Answer:y = 4x + 16

Step-by-step explanation:You can replace the point coordinates in the given point-slope form to get …

y – 32 = 4(x -4)

Then rearrange to put this into slope-intercept form.

y = 4x -16 +32 . . . . eliminate parentheses, add 32

y = 4x +16. . . . . . . . simplify