C
What is the equation of the line that is parallel to the line y – 1 = 4(x + 3) and passes through the point (4, 32)?
SER
O y=-*x+33
y=-*x+36
O y =
O y = 4x – 16
O y = 4x + 16
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Question
C
What is the equation of the line that is parallel to the line y – 1 = 4(x + 3) and passes through the point (4, 32)?
SER
O y=-*x+33
y=-*x+36
O y =
O y = 4x – 16
O y = 4x + 16
Mark this and retum
Save and Exit
Nex
Submit
9514 1404 393
Answer:
y = 4x + 16
Step-by-step explanation:
You can replace the point coordinates in the given point-slope form to get …
y – 32 = 4(x -4)
Then rearrange to put this into slope-intercept form.
y = 4x -16 +32 . . . . eliminate parentheses, add 32
y = 4x +16 . . . . . . . . simplify