At a carnival, you can try to ring a bell by striking a target with a 11.7-kg hammer. In response, a 0.378-kg metal piece is sent upward tow

Question

At a carnival, you can try to ring a bell by striking a target with a 11.7-kg hammer. In response, a 0.378-kg metal piece is sent upward toward the bell, which is 5.13 m above. Suppose that 18.0 percent of the hammer’s kinetic energy is used to do the work of sending the metal piece upward. How fast must the hammer be moving when it strikes the target so that the bell just barely rings

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Delwyn 3 years 2021-08-10T20:29:00+00:00 2 Answers 15 views 0

Answers ( )

  1. Thunguyet
    0
    2021-08-10T20:30:01+00:00
    Reply

    Answer:

    Explanation:

    mass of hammer, Mh = 11.7 kg

    mass of metal, Mm = 0.378 kg

    height, h = 5.13 m

    According to the transformation of energy

    Potential energy of metal piece = 18% of kinetic energy of hammer

    Mm x g x h = 18 % of 0.5 x Mh x v²

    where, v is the velocity of hammer

    0.378 x 9.8 x 5.3 = 0.18 x 0.5 x 11.7 x v²

    v² = 18.65

    v = 4.31 m/s

    Thus, the velocity of hammer is 4.31 m/s.

  2. sori
    0
    2021-08-10T20:30:06+00:00
    Reply

    Answer:

    4.25035202162 m/s

    Explanation:

    m_h = Mass of hammer = 11.7 kg

    m_m = Mass of metal piece = 0.378 kg

    g = Acceleration due to gravity = 9.81\ m/s^2

    h = Height = 5.13 m

    Energy required to raise the bell

    U=m_mgh\\\Rightarrow U=0.378\times 9.81\times 5.13\\\Rightarrow U=19.0229634\ J

    From the question we have

    19.0229634=0.18\times \dfrac{1}{2}m_h\times v^2\\\Rightarrow v=\sqrt{\dfrac{19.0229634\times 2}{0.18\times 11.7}}\\\Rightarrow v=4.25035202162\ m/s

    The speed of the metal piece is 4.25035202162 m/s

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