ASAP: #43. Find the area of triangle ABC given A = 42.5°, b = 13.6, c = 10.1 (Draw a triangle, give answer to nearest tenth!) Co

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ASAP: #43. Find the area of triangle ABC given A = 42.5°, b = 13.6, c = 10.1 (Draw a triangle, give answer to nearest tenth!)

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Thành Công 4 years 2021-08-04T23:16:47+00:00 1 Answers 13 views 0

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  1. thienthanh
    0
    2021-08-04T23:18:44+00:00
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    Answer:

    The area of a triangle  A = 46.399 square units

    Step-by-step explanation:

    Explanation:-

    Given that ΔABC

    Given ∠ A = 42.5° and sides b= 13.6 and c =10.1

    The area of a triangle

                    A = \frac{1}{2} b c sin A

                    A = \frac{1}{2} 13.6(10.1) sin 42.5

                    A = \frac{1}{2} 137.36(0.67559)         (∵ sin (42.5)° = 0.67559

                   A = 46.399 square units

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