ASAP: #43. Find the area of triangle ABC given A = 42.5°, b = 13.6, c = 10.1 (Draw a triangle, give answer to nearest tenth!)

Correct answer gets marked brainliest:)

ASAP: #43. Find the area of triangle ABC given A = 42.5°, b = 13.6, c = 10.1 (Draw a triangle, give answer to nearest tenth!)

Correct answer gets marked brainliest:)

Answer:The area of a triangle A = 46.399 square units

Step-by-step explanation:Explanation:-Given that ΔABC

Given ∠ A = 42.5° and sides b= 13.6 and c =10.1

The area of a triangle

[tex]A = \frac{1}{2} b c sin A[/tex]

[tex]A = \frac{1}{2} 13.6(10.1) sin 42.5[/tex]

[tex]A = \frac{1}{2} 137.36(0.67559)[/tex] (∵ sin (42.5)° = 0.67559

A = 46.399 square units