An oven consumes 425 kWh of energy in order to provide 386 kWh of useful energy. What is its percent efficiency?

Question

An oven consumes 425 kWh of energy in order to provide 386 kWh of useful energy. What is its percent efficiency?

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Jezebel 5 years 2021-07-24T08:50:09+00:00 1 Answers 41 views 0

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  1. mocmien2
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    2021-07-24T08:51:54+00:00
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    Answer:

    90.8%

    Explanation:

    efficiency = output / input

    Simply just put in what we know.

    386/425 = 0.908 (Rounded too 3 s.f)

    And if you want this in percentage, you simply x100 your answer. Hence the answer being 90.8%

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