an object that is 15 cm tall is placed 44 cm in front of a diverging lens. A virtual image appears -14cm in front of the lens. determine the

Question

an object that is 15 cm tall is placed 44 cm in front of a diverging lens. A virtual image appears -14cm in front of the lens. determine the focal length of the lens .
SHOW YOUR WORK.
A) 0.09cm
B)-20.53cm
C)10.6cm
D)-0.04cm

in progress 0
Thu Thảo 3 years 2021-07-22T03:34:39+00:00 1 Answers 27 views 0

Answers ( )

  1. Delwyn
    0
    2021-07-22T03:36:26+00:00
    Reply

    Answer:

    The correct option is (b).

    Explanation:

    Given that,

    The height of the object, h = 15 cm

    Object distance, u = -44 cm

    Image distance, v = -14 cm

    We need to find the focal length of the lens. Using the lens formula.

    \dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}\\\\\dfrac{1}{f}=\dfrac{1}{(-14)}-\dfrac{1}{(-44)}\\\\f=-20.53\ cm

    So, the focal length of the lens (-20.53 cm).

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )