an object that is 15 cm tall is placed 44 cm in front of a diverging lens. A virtual image appears -14cm in front of the lens. determine the

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an object that is 15 cm tall is placed 44 cm in front of a diverging lens. A virtual image appears -14cm in front of the lens. determine the focal length of the lens .
SHOW YOUR WORK.
A) 0.09cm
B)-20.53cm
C)10.6cm
D)-0.04cm

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  1. Answer:

    The correct option is (b).

    Explanation:

    Given that,

    The height of the object, h = 15 cm

    Object distance, u = -44 cm

    Image distance, v = -14 cm

    We need to find the focal length of the lens. Using the lens formula.

    [tex]\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}\\\\\dfrac{1}{f}=\dfrac{1}{(-14)}-\dfrac{1}{(-44)}\\\\f=-20.53\ cm[/tex]

    So, the focal length of the lens (-20.53 cm).

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