An electric field is given by in units of N/C when is in meters. What is the potential difference from point B at (0,7) m to point A at (7,0

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An electric field is given by in units of N/C when is in meters. What is the potential difference from point B at (0,7) m to point A at (7,0) m

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Thạch Thảo 5 years 2021-07-18T17:40:44+00:00 1 Answers 80 views 0

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  1. Ben
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    2021-07-18T17:41:45+00:00
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    Complete Question

    An electric field is given by E= (5x, 0, 0) in units of N/C when x is in meters. What is the potential difference VA – VB from point B at (0,7) m to point A at (7,0) m? V

    Answer:

    V_A-V_B=-122.5V

    Explanation:

    From the question we are told that:

    Position of point B=(0,7) m

    Position of point A=(7,0) m

    Generally the equation for pd across the points is mathematically given by

     V_A-V_B=-\int_0^7(5x)d

     V_A-V_B=-[\frac{5x^2}{2}]_0^7

     V_A-V_B=-[\frac{5(7)^2}{2}]

     V_A-V_B=-122.5V

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