An airplane takes off 200 yards in front of a 60 foot building. At what angle of elevation must the plane take off in order to avoid c

Question

An airplane takes off 200 yards in front of a 60 foot building. At what angle of elevation must the plane
take off in order to avoid crashing into the building?

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Doris 3 years 2021-09-05T06:02:45+00:00 1 Answers 154 views 0

Answers ( )

  1. thuhuong
    0
    2021-09-05T06:03:51+00:00
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    Answer:

    16.69°

    Step-by-step explanation:

    Given that,

    Height of the building, h = 60 foot

    Distance from the base of the building, b = 60 foot

    We need to find the angle of elevation must the plane takes off in order to avoid crashing into the building. So,

    \tan\theta=\dfrac{60}{200}\\\\\theta=\tan^{-1}\dfrac{60}{200}\\\\=16.69^{\circ}

    So, the required angle is 16.69°.

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