A volleyball is spiked so that its incoming velocity of +2.09 m/s is changed to an outgoing velocity of -24.6 m/s. The mass of the volleybal

Question

A volleyball is spiked so that its incoming velocity of +2.09 m/s is changed to an outgoing velocity of -24.6 m/s. The mass of the volleyball is 0.350 kg. What is the magnitude of the impulse that the player applies to the ball?

in progress 0
Amity 5 years 2021-07-22T16:17:48+00:00 1 Answers 46 views 0

Answers ( )

  1. bonexptip
    0
    2021-07-22T16:19:17+00:00
    Reply

    Answer:

    Impulse, J = 9.34 kg-m/s

    Explanation:

    Given that,

    Mass of the volleyball, m = 0.35 kg

    Initial velocity, u = +2.09 m/s

    Final speed, v = -24.6 m/s

    We need to find the magnitude of the impulse that the player applies to the ball. We know that impulse is equal to the change in momentum . So,

    J=m(v-u)\\\\J=0.35\times (-24.6-2.09)\\\\J=-9.34\ kg-m/s

    So, the magnitude of the impulse that the player applies to the ball is 9.34 kg-m/s.

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )