A transverse, wave travelling on a chord is represented by D=0.22sin (5.6x+34t) where D and x are inmeters and t is in seconds. For this wave, determine; a) wavelength b) frequency c) velocity (both magnitude and direction) d) amplitude e) maximum and minimum speed of particles in the chord.

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Answer:a) λ = 1.12 m

b) f = 5.41 Hz

c) v = 154.54 m/s

d) A = 0.22m

e)

Explanation:You have the following equation for a wave traveling on a cord:

(1)The general expression for a wave is given by:

(2)By comparing the equation (1) and (2) you have:

A: amplitude of the wave = 0.22m

k: wave number = 5.6 m^-1

w: angular velocity = 34 rad/s

a)The wavelength is given by substitution in the following expression:b)The frequency is:c)The velocity of the wave is:d)The amplitude is0.22me)To calculate the maximum and minimum speed of the particles you obtain the derivative of the equation of the wave, in time:cos function has a minimum value -1 and maximum +1.

Then, you obtain for maximum and minimum velocity: