A transverse, wave travelling on a chord is represented by D=0.22sin (5.6x+34t) where D and x are inmeters and t is in seconds. For this wave, determine; a) wavelength b) frequency c) velocity (both magnitude and direction) d) amplitude e) maximum and minimum speed of particles in the chord.


  1. Answer:

    a) λ = 1.12 m

    b) f = 5.41 Hz

    c) v = 154.54 m/s

    d) A = 0.22m




    You have the following equation for a wave traveling on a cord:

    D=0.22sin(5.6x+34t)     (1)

    The general expression for a wave is given by:

    D=Asin(kx-\omega t)    (2)

    By comparing the equation (1) and (2) you have:

    A: amplitude of the wave = 0.22m

    k: wave number = 5.6 m^-1

    w: angular velocity = 34 rad/s

    a) The wavelength is given by substitution in the following expression:


    b) The frequency is:


    c) The velocity of the wave is:


    d) The amplitude is 0.22m

    e) To calculate the maximum and minimum speed of the particles you obtain the derivative of  the equation of the wave, in time:


    cos function has a minimum value -1 and maximum +1. Then, you obtain for maximum and minimum velocity:


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