A tennis ball of mass m = 0.08 kg and speed v=29 ms strikes a wall at a 45∘ angle and rebounds with the same speed at 45∘. What is the magni

Question

A tennis ball of mass m = 0.08 kg and speed v=29 ms strikes a wall at a 45∘ angle and rebounds with the same speed at 45∘. What is the magnitude of the impulse given to the ball? Express your answer to two significant figures and include the appropriate units.

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Thu Nguyệt 5 years 2021-07-26T15:26:24+00:00 1 Answers 11 views 0

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  1. ThanhThu
    0
    2021-07-26T15:27:48+00:00
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    Answer:

    3.3 kg-m/s

    Explanation:

    The mass of the ball m = 0.08 kg

    speed v_{1} = 29 m/s

    angle oat which its strikes the wall = 45°

    Final speed of reboundv_{2} = 29 m/s

    angle of rebound = 45°

    Momentum before collision p_{1} = mv_{1} cos ∅

    ==> 0.08 x 29 cos 45 = 1.64 kg-m/s

    since the same variables are maintained in the rebound, then the momentum of rebound will be of the same magnitude, but in the opposite direction

    p_{2} = -1.64 kg-m/s

    The impulse is the change of momentum I = p_{1}  – p_{2}

    I = 1.64 – (-1.64 ) = 1.64  + 1.64  = 3.3 kg-m/s

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