A student is trying to solve the system of two equations given below: Equation P: y + z = 6 Equation Q: 8y + 7z = 1 <

Question

A student is trying to solve the system of two equations given below:

Equation P: y + z = 6
Equation Q: 8y + 7z = 1

Which of the following is a possible step used in eliminating the y-term?

(y + z = 6) ⋅ −8
(y + z = 6) ⋅ 7
(8y + 7z = 1) ⋅ 7
(8y + 7z = 1) ⋅ 8

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King 5 years 2021-07-19T13:30:53+00:00 2 Answers 75 views 0

Answers ( )

  1. Philomena
    0
    2021-07-19T13:32:40+00:00
    Reply

    Answer:

    (y+z=6)-8

    Step-by-step explanation:

    You have to eliminate y. You already have 8y. What eliminates 8y? -8y. And if you simplify (y+z=6)-8, you’ll get -8y-8z=-48.

  2. binhan
    0
    2021-07-19T13:32:43+00:00
    Reply

    Answer:

    A. (y+z=6) -8

    Step-by-step explanation:

    You will use the process of adding together the like terms. Since in equation Q, we have 8y, we need -8y in equation P. Answer A is the only one that will give us -8. You have to distribute -8 across all the variables and numbers in the parenthesis.

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