A spherical party balloon is being inflated with helium pumped in at a rate of 4 cubic feet per minute. How fast is the radius growing at th

Question

A spherical party balloon is being inflated with helium pumped in at a rate of 4 cubic feet per minute. How fast is the radius growing at the instant when the radius has reached 2 ft

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Đan Thu 5 years 2021-08-29T04:35:30+00:00 1 Answers 19 views 0

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  1. minhkhang
    0
    2021-08-29T04:36:46+00:00
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    Answer:

    0.159 ft/min

    Explanation:

    v= 4/3πr³

    dv/dt = 8

    dv/dt = 4/3π( 3r²) ( dr/dt
    )

    plugging the values

     
    8=4/3π( 3r²) ( dr/dt
    )

    dr/dt= 1/(6.28)=0.159 ft per min approx

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