A small electric motor is used to lift a 0.50-kilogram mass at constant speed. If the mass is lifted a vertical distance of 1.5 meters in 5.

Question

A small electric motor is used to lift a 0.50-kilogram mass at constant speed. If the mass is lifted a vertical distance of 1.5 meters in 5.0 seconds, the average power developed by the motor is

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Ngọc Khuê 5 years 2021-08-01T11:00:36+00:00 1 Answers 185 views 1

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  1. yenoanh
    0
    2021-08-01T11:02:08+00:00
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    Answer:

    Power developed by the motor is 1.47 W

    Explanation:

    As we know that mechanical power is defined as the ratio of work done per unit time

    here we know that work done to lift the mass upward is given as

    W = mgh

    here we have

    m = 0.50 kg

    h = 1.5 m

    so we have

    W = 0.50(9.81)(1.5)

    W = 7.36 J

    now it took 5 s to lift the mass so we have

    P = \frac{W}{t}

    P = \frac{7.36}{5}

    P = 1.47 W

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