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A simple pendulum consists of a 4.9-kg mass attached to a string. The pendulum is pulled to the right and held at rest so that it is 2.08 m
Question
A simple pendulum consists of a 4.9-kg mass attached to a string. The pendulum is pulled to the right and held at rest so that it is 2.08 m above the lowest point in its swing. If you let it go from this point, how fast (in m/s) is it traveling at the lowest point of its swing (on the initial pass)
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Physics
3 years
2021-08-13T17:14:22+00:00
2021-08-13T17:14:22+00:00 1 Answers
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Answers ( )
Answer:
6.384 m/![Rendered by QuickLaTeX.com sec^{2}](https://documen.tv/wp-content/ql-cache/quicklatex.com-b9d645a195d062c14f2926f37397aa61_l3.png)
Explanation:
The velocity is given by;
We know;
PE= mgh
KE= 1/2 m![Rendered by QuickLaTeX.com V^{2}](https://documen.tv/wp-content/ql-cache/quicklatex.com-3fde41ee7e6621103510e8f6d80f5996_l3.png)
but KE=PE
==> 1/2 m
=mgh
==> 1/2
=gh
==>![Rendered by QuickLaTeX.com v=\sqrt{2gh}](https://documen.tv/wp-content/ql-cache/quicklatex.com-b8b62cb20356dd00840bbb4dbb459745_l3.png)
puting g=9.8 m/sec2
h=2.08 m
==>
=