A simple pendulum consists of a 4.9-kg mass attached to a string. The pendulum is pulled to the right and held at rest so that it is 2.08 m

Question

A simple pendulum consists of a 4.9-kg mass attached to a string. The pendulum is pulled to the right and held at rest so that it is 2.08 m above the lowest point in its swing. If you let it go from this point, how fast (in m/s) is it traveling at the lowest point of its swing (on the initial pass)

in progress 0
Delwyn 4 years 2021-08-13T17:14:22+00:00 1 Answers 11 views 0

Answers ( )

  1. Delwyn
    0
    2021-08-13T17:15:57+00:00
    Reply

    Answer:

    6.384 m/sec^{2}

    Explanation:

    The velocity is given by;

    We know;

    PE= mgh

    KE= 1/2 mV^{2}

    but KE=PE

    ==> 1/2 mV^{2} =mgh

    ==> 1/2 V^{2} =gh

    ==> v=\sqrt{2gh}

    puting g=9.8 m/sec2

    h=2.08 m

    ==> v= 6.384 m/sec^{2}=

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )