A researcher studying the nutritional value of a new candy places a 4.60 g sample of the candy inside a bomb calorimeter and combusts it in

A researcher studying the nutritional value of a new candy places a 4.60 g sample of the candy inside a bomb calorimeter and combusts it in excess oxygen. The observed temperature increase is 2.69 ∘ C. If the heat capacity of the calorimeter is 32.20 kJ ⋅ K − 1 , how many nutritional Calories are there per gram of the candy?

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  1. Answer:

    4500.5 nutritional calories per gram

    Explanation:

    Heat lost by the new candy = heat gained by the bomb calorimeter.

    Heat gained by the bomb calorimeter = c×ΔT

    where c = heat capacity of the calorimeter = 32.20 KJ/K = 32200 J/K

    ΔT = change in temperature = 2.69°C = 2.69 K.

    Heat gained by the bomb calorimeter = 32200 × 2.69 = 86618 J

    Heat lost by the new candy = heat gained by the bomb calorimeter = 86618 J = 20702.2 calories

    4.60 g of the new candy lost this amount of calories by undergoing combustion,

    The amount of calories per g = 20702.2 calories/4.6 g = 4500.5 calories per gram

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