Question A rectangle measures 8.5 cm by 10.7 cm both correct to 1 decimal place.Calculate the upper bound of the perimeter of the rectangle

Answer: The perimeter of the rectangle = 38.4cm Step-by-step explanation: Explanation:- Given that the length of the rectangle(l) = 8.5cm The width of the rectangle(w) = 10.7cm The perimeter of the rectangle P = 2(l+w) P = 2( 8.5 + 10.7) P = 2 ×19.2 = 38.4 cm The perimeter of the rectangle = 38.4cm Log in to Reply

Answer:The perimeter of the rectangle = 38.4cm

Step-by-step explanation:Explanation:-Given that the length of the rectangle(l) = 8.5cm

The width of the rectangle(w) = 10.7cm

The perimeter of the rectangle

P = 2(l+w)

P = 2( 8.5 + 10.7)

P = 2 ×19.2 = 38.4 cm

The perimeter of the rectangle = 38.4cm