A quantity with an initial value of 720 decays continuously at a rate of 9% per hour. What is the value of the quantity after 69 hours, to t

Question

A quantity with an initial value of 720 decays continuously at a rate of 9% per hour. What is the value of the quantity after 69 hours, to the nearest hundredth?

in progress 0
Calantha 3 years 2021-07-20T04:07:50+00:00 1 Answers 40 views 0

Answers ( )

  1. trucchi
    0
    2021-07-20T04:09:46+00:00
    Reply

    Answer:

    1.45

    Step-by-step explanation:

    f(t)=720e^rt

    f(t)=720e

    rt

    Continuously uses Pe^(rt)

    r\text{: decays }9\% \

    r: decays 9%→−0.09

    per hour

    f(t)=720e^{-0.09t}

    f(t)=720e

    −0.09t

    (where t is in hours)

    69\text{ hours: no time conversion necessary}

    69 hours: no time conversion necessary

    hours are the only units in the problem.

    \text{Plug in }t=69

    Plug in t=69

    f(69)=720e^{-0.09(69)}

    f(69)=720e

    −0.09(69)

    1.44665097413

    1.44665097413

    \approx 1.45

    ≈1.45

    Round to the nearest hundredth

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )