A proton at location A makes an electricfield E–>1 atlocation B. A different proton, placed atlocation B, experiences a force F=>1.

Question

A proton at location A makes an electricfield E–>1 atlocation B. A different proton, placed atlocation B, experiences a force F—>1.
If |E–>|= 300 N/C, what is |F–>1|?
|F–>1|= N
Now the proton at B is removed and replaced by alithium nucleus, containing three protons and four neutrons. Theproton at location A remains in place.
What is the magnitude of the electric force on the lithium nucleus?
|F–>Li| = N
Now the Lithium nucleus is removed, and an electron is placed atlocation B. The proton atlocation A remains in place. What is the magnitude of the electric force on the electron?
|F–>1| = N

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Tryphena 5 years 2021-08-01T04:53:46+00:00 1 Answers 67 views 0

Answers ( )

  1. Helga
    0
    2021-08-01T04:55:40+00:00
    Reply

    Answer:

    Explanation:

     |F–>1| =  E–>1 x charge on proton

    = 300 x 1.6 x 10⁻¹⁹

    Magnitude of electric force on proton

    |F–>1| = 480 x 10⁻¹⁹ N .

    Inside lithium nucleus , there are three protons so charge on it

    = 3 x 1.6 x 10⁻¹⁹ = 4.8 x 10⁻¹⁹ C .

    Magnitude of electric force on lithium nucleus

    |F–>Li|  =   E–>1 x charge on lithium nucleus

    = 300 x  4.8 x 10⁻¹⁹

    = 1440 x 10⁻¹⁹ N .

    Electron has same charge as that possessed by proton so charge on electron = 1.6 x 10⁻¹⁹ C

    Magnitude of force on electron

    |F–>1| =  E–>1 x charge on electron

    = 300 x 1.6 x 10⁻¹⁹

    =  480 x 10⁻¹⁹ N .

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