a pitcher threw a baseball straight up at 35.8 meters per second. what was the balls velocity after 2.50?

Question

a pitcher threw a baseball straight up at 35.8 meters per second. what was the balls velocity after 2.50?

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bonexptip 5 years 2021-08-11T08:48:09+00:00 1 Answers 301 views 0

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  1. haidang
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    2021-08-11T08:49:12+00:00
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    Answer:

    v=11.3 ms^{-1}

    Explanation:

    According to question, a pitcher threw a baseball straight up at 35.8 meters per second.

    Use the expression of the equation of motion.

    v= u+at

    Here, v is the final velocity.

    Put a= g= -9.8 ms^{-2}, t= 2.50 s, u=35.8 ms^{-1} and u = 0.

    v= 35.8+ (-9.8)\times 2.50

    v=11.3 ms^{-1}

    Therefore, the velocity of ball after 2.50 s is v=11.3 ms^{-1}.

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