a motorcycle is trying to leap across the canyon by driving horizontally off a cliff 38 m/s. Ignoring air resistance, find the speed with wh

Question

a motorcycle is trying to leap across the canyon by driving horizontally off a cliff 38 m/s. Ignoring air resistance, find the speed with which the cycle strikes the ground on the other side

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Adela 5 years 2021-08-05T04:49:55+00:00 1 Answers 23 views 0

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  1. Xavia
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    2021-08-05T04:51:00+00:00
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    Answer:

    46.15m/s

    Explanation:

    We are given that

    Initial speed,u=38 m/s

    Height of cliff,h=70 m

    We have to find the speed with which the cycle strikes the ground at a height 35 m on the other side.

    h’=35 m

    Using conservation law of energy

    \frac{1}{2}mu^2+mgh=\frac{1}{2}mv^2+mgh'

    \frac{1}{2}u^2+gh=\frac{1}{2}v^2+gh'

    Where g=9.8m/s^2

    Substitute the values

    \frac{1}{2}(38)^2+9.8\times 70=\frac{1}{2}v^2+9.8\times 35

    \frac{1}{2}v^2=\frac{1}{2}(38)^2+9.8\times 70-9.8\times 35=1065

    v=\sqrt{2\times 1065}

    v=46.15m/s

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