A mixture of nitrogen and argon gas is expanded from a volume of to a volume of 62 L to 84 L, while the pressure is held constant at 96 atm

Question

A mixture of nitrogen and argon gas is expanded from a volume of to a volume of 62 L to 84 L, while the pressure is held constant at 96 atm . Calculate the work done on the gas mixture. Round your answer to significant digits, and be sure it has the correct sign (positive or negative).

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Bơ 4 years 2021-08-25T10:59:38+00:00 1 Answers 9 views 0

Answers ( )

  1. mit
    0
    2021-08-25T11:00:53+00:00
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    Explanation:

    The given data is as follows.

            P = 96 atm,         V_{i} = 62 L

         V_{f} = 84 L

    Now, we know that the relation between work and pressure is as follows.

              W = -P_{ext}(V_{f} - V_{i})

    Putting the given values into the above formula we will calculate the work done as follows.

                W = -P_{ext}(V_{f} - V_{i})

                    = -96 (84 - 62)

                    = -2112 J

    or,            = -211.2 kJ     (as 1 kJ = 1000 J)

    Thus, we can conclude that the work done on the gas mixture is 211.2 kJ.

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