A mixture of nitrogen and argon gas is expanded from a volume of to a volume of 62 L to 84 L, while the pressure is held constant at 96 atm . Calculate the work done on the gas mixture. Round your answer to significant digits, and be sure it has the correct sign (positive or negative).
Question
Explanation:
The given data is as follows.
P = 96 atm, [tex]V_{i}[/tex] = 62 L
[tex]V_{f}[/tex] = 84 L
Now, we know that the relation between work and pressure is as follows.
W = [tex]-P_{ext}(V_{f} – V_{i})[/tex]
Putting the given values into the above formula we will calculate the work done as follows.
W = [tex]-P_{ext}(V_{f} – V_{i})[/tex]
= [tex]-96 (84 – 62)[/tex]
= -2112 J
or, = -211.2 kJ (as 1 kJ = 1000 J)
Thus, we can conclude that the work done on the gas mixture is 211.2 kJ.