A laser beam is incident from the air at an angle of 30.0° to the vertical onto a solution of Karo syrup in water. If the beam is refracted to 19.24° to the vertical, what is the index of refraction of the syrup solution?

Answers

Answer:

Index of Refraction = 1.52

Explanation:

The index of refraction or the refractive index is given as:

Index of Refraction = Sin i/Sin r

where,

i = angle of incidence

r = angle of refraction

In this case of karo syrup, we have the following data:

i = angle of incidence = 30°

r = angle of refraction = 19.24°

Therefore, substituting these values in the equation, we get:

Index of Refraction = Sin 30°/Sin 19.24°

Index of Refraction = 0.5/0.3295

Index of Refraction = 1.52

Hence, the refractive index or the index of refraction of the Karo Syrup is found to be 1.52.

Answer:Index of Refraction = 1.52

Explanation:The index of refraction or the refractive index is given as:

Index of Refraction = Sin i/Sin rwhere,

i = angle of incidence

r = angle of refraction

In this case of karo syrup, we have the following data:

i = angle of incidence = 30°

r = angle of refraction = 19.24°

Therefore, substituting these values in the equation, we get:

Index of Refraction = Sin 30°/Sin 19.24°Index of Refraction = 0.5/0.3295Index of Refraction = 1.52Hence, the refractive index or the index of refraction of the Karo Syrup is found to be

1.52.