A hydrometre with a uniform cross-sectional area floats in a liquid of density 0.80cm^-3.If the hydrometre wieighs 100.0g and has 12.0cm of

Question

A hydrometre with a uniform cross-sectional area floats in a liquid of density 0.80cm^-3.If the hydrometre wieighs 100.0g and has 12.0cm of its length below the liquid surface , calculate the cross-sectional area of the hydrometre

in progress 0
Thiên Ân 5 years 2021-07-22T01:09:06+00:00 1 Answers 131 views 1

Answers ( )

  1. ngochoa
    1
    2021-07-22T01:10:21+00:00
    Reply

    Answer:

    Explanation:

    Let the cross sectional area be a cm .

    volume of hydrometer inside liquid = 12 x a = 12 a

    weight of liquid displaced = 12a x .8 x g = 9.6 a g

    For free floatation of liquid

    weight of hydrometer = weight of displaced liquid

    9.6 a g = 100 g

    a = 10.41 cm²

    cross sectional area = 10.41 cm².

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )