A hovercraft takes off from a platform. Its height (in meters), x xx seconds after takeoff, is modeled by h ( x ) = − ( x − 11 ) ( x + 3 ) h(x)=−(x−11)(x+3)h, left parenthesis, x, right parenthesis, equals, minus, left parenthesis, x, minus, 11, right parenthesis, left parenthesis, x, plus, 3, right parenthesis What is the height of the hovercraft at the time of takeoff?

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Answer: 33 seconds

Step-by-step explanation: Khan Academy

Answer:3²/₃ m

Step-by-step explanation:Since h(x)= −(x−11)(x+3) represents the height of the hovercraft after x seconds, at the time of takeoff, x = 0.

So, the height at takeoff is h(0) = −(0 − 11)(0 + 3)

= -(-11)/3

= 11/3 m

= 3²/₃ m