A hovercraft takes off from a platform. Its height (in meters), x xx seconds after takeoff, is modeled by h ( x ) = − ( x − 11 ) ( x + 3 )

Question

A hovercraft takes off from a platform. Its height (in meters), x xx seconds after takeoff, is modeled by h ( x ) = − ( x − 11 ) ( x + 3 ) h(x)=−(x−11)(x+3)h, left parenthesis, x, right parenthesis, equals, minus, left parenthesis, x, minus, 11, right parenthesis, left parenthesis, x, plus, 3, right parenthesis What is the height of the hovercraft at the time of takeoff?

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Philomena 4 years 2021-08-17T15:34:54+00:00 2 Answers 228 views 0

Answers ( )

  1. Ladonna
    0
    2021-08-17T15:36:17+00:00
    Reply

    Answer: 33 seconds

    Step-by-step explanation: Khan Academy

  2. thanhcong
    0
    2021-08-17T15:36:50+00:00
    Reply

    Answer:

    3²/₃ m

    Step-by-step explanation:

    Since h(x)= −(x−11)(x+3) represents the height of the hovercraft after x seconds, at the time of takeoff, x = 0.

    So, the height at takeoff is h(0) = −(0 − 11)(0 + 3)

    = -(-11)/3

    = 11/3 m

    = 3²/₃ m

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