A hovercraft takes off from a platform. It’s height (in meters), x seconds after takeoff, is modeled by h(x)=-(x-11)(x+3) How many seconds a

Question

A hovercraft takes off from a platform. It’s height (in meters), x seconds after takeoff, is modeled by h(x)=-(x-11)(x+3) How many seconds after takeoff will the hovercraft land on the ground?

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Khoii Minh 5 years 2021-08-05T16:15:09+00:00 1 Answers 113 views 0

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  1. quangkhai
    0
    2021-08-05T16:16:11+00:00
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    Answer:

    11seconds

    Step-by-step explanation:

    Given the height of the hovercraft expressed as;

    (x)=-(x-11)(x+3)

    The height of the hovercraft on the ground is 0, hence;

    0 =-(x-11)(x+3)

    -(x-11)(x+3) = 0

    Multiply both sides by minus

    (x-11)(x+3) = 0

    x-11 = 0 and x+3=0

    x = 11 and -3

    Since time cannot be negative, hence the hovercraft will land after 11seconds

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