A garden that is 14 feet by 17 feet will have a pedestrian pathway on the border, making the combined area of the garden and the border 311

Question

A garden that is 14 feet by 17 feet will have a pedestrian pathway on the border, making the combined area of the garden and the border 311 square feet what is the width of the pathway

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Tryphena 5 years 2021-08-29T04:52:12+00:00 1 Answers 27 views 0

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    2021-08-29T04:53:24+00:00

    Answer:

    The width of the pathway is 5.2 feet

    Step-by-step explanation:

    Given that the shape of the garden and the walkway is a rectangle, the walkway would have the same length as the garden but would have it’s own width.

    Let the width of the garden be W and that of the walkway be t while the length of both the garden and walkway is L. The combined area A

    = L( W + t)

    Given that the combined area of the garden and the border 311 square feet while the garden is  14 feet by 17 feet

    311 = 14 (17 + t)

    311 = 238 + 14t

    collect like terms

    14t = 311 – 238

    14t = 73

    t = 73/14

    = 5.2 feet

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