A galvanic cell whose cell reaction is 2Fe3+(aq) + Zn(s) → 2Fe2+(aq) + Zn2+(aq) has a cell potential of 0.72V. What is the maximum electrica

Question

A galvanic cell whose cell reaction is 2Fe3+(aq) + Zn(s) → 2Fe2+(aq) + Zn2+(aq) has a cell potential of 0.72V. What is the maximum electrical work that can be obtained from this cell per mole of iron(III) ion?

in progress 0
Ladonna 5 years 2021-08-11T09:42:27+00:00 1 Answers 173 views 0

Answers ( )

  1. Delwyn
    0
    2021-08-11T09:43:52+00:00
    Reply

    Answer:

    138.96kJ is the maximum electrical work

    Explanation:

    The maximum electrical work that can be obtained from a cell is obtained from the equation:

    W = -nFE

    Where W is work in Joules,

    n are moles of electrons = 2mol e- because half-reaction of Zn is:

    Zn(s) → Zn²⁺(aq) + 2e⁻

    F is faraday constant = 96500Coulombs/mol

    E is cell potential = 0.72V

    Replacing:

    W = -2mol*96500Coulombs/mol*0.72V

    W = – 138960J =

    138.96kJ is the maximum electrical work

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )