A flat coil of wire consisting of 15 turns, each with an area of 40 cm 2, is positioned perpendicularly to a uniform magnetic field that inc

Question

A flat coil of wire consisting of 15 turns, each with an area of 40 cm 2, is positioned perpendicularly to a uniform magnetic field that increases its magnitude at a constant rate from 1.5 T to 5.1 T in 2.0 s. If the coil has a total resistance of 0.20 Ω, what is the magnitude of the induced current?

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Xavia 5 years 2021-07-14T15:26:34+00:00 1 Answers 16 views 0

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  1. thongdat2
    0
    2021-07-14T15:27:54+00:00
    Reply

    Answer:

    0.54 A

    Explanation:

    Parameters given:

    Number of turns, N = 15

    Area of coil, A = 40 cm² = 0.004 m²

    Change in magnetic field, ΔB = 5.1 – 1.5 = 3.6 T

    Time interval, Δt = 2 secs

    Resistance of the coil, R = 0.2 ohms

    To get the magnitude of the current, we have to first find the magnitude of the EMF induced in the coil:

    |V| = |(-N * ΔB * A) /Δt)

    |V| = | (-15 * 3.6 * 0.004) / 2 |

    |V| = 0.108 V

    According to Ohm’s law:

    |V| = |I| * R

    |I| = |V| / R

    |I| = 0.108 / 0.2

    |I| = 0.54 A

    The magnitude of the current in the coil of wire is 0.54 A

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