. A convertible moves toward you and then passes you; all the while, its loudspeakers are producing a sound. The speed of the car is a const

Question

. A convertible moves toward you and then passes you; all the while, its loudspeakers are producing a sound. The speed of the car is a constant 9.30 m/s, and the speed of sound is 342 m/s. What is the ratio of the frequency you hear while the car is approaching to the frequency you hear while the car is moving away

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Dulcie 5 years 2021-08-17T13:04:31+00:00 1 Answers 23 views 0

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  1. thienthanh
    0
    2021-08-17T13:06:09+00:00
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    Answer:

    1.056

    Explanation:

    v = Velocity of sound = 342 m/s

    v_s = Velocity of source of sound = 9.3 m/s

    f_a = Frequency when car is approaching

    f_m = Frequency when car is moving away

    f_s = Frequecy of source of sound

    The required ratio is

    \dfrac{f_a}{f_m}=\dfrac{\dfrac{v}{v-v_s}f_s}{\dfrac{v}{v+v_s}f_s}\\\Rightarrow \dfrac{f_a}{f_m}=\dfrac{v+v_s}{v-v_s}\\\Rightarrow \dfrac{f_a}{f_m}=\dfrac{342+9.3}{342-9.3}\\\Rightarrow \dfrac{f_a}{f_m}=1.056

    The ratio of the frequency you hear while the car is approaching to the frequency you hear while the car is moving away is 1.056

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